Optimal. Leaf size=377 \[ \frac{2 \left (66 a^2 b^2 (5 A+7 C)+5 a^4 (9 A+11 C)+77 b^4 (A+3 C)\right ) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{231 d}-\frac{8 a b \left (a^2 (7 A+9 C)+3 b^2 (3 A+5 C)\right ) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{15 d}+\frac{2 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{231 d \cos ^{\frac{7}{2}}(c+d x)}+\frac{2 \left (9 a^2 b^2 (101 A+143 C)+15 a^4 (9 A+11 C)+64 A b^4\right ) \sin (c+d x)}{693 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{4 a b \left (a^2 (673 A+891 C)+96 A b^2\right ) \sin (c+d x)}{3465 d \cos ^{\frac{5}{2}}(c+d x)}+\frac{8 a b \left (a^2 (7 A+9 C)+3 b^2 (3 A+5 C)\right ) \sin (c+d x)}{15 d \sqrt{\cos (c+d x)}}+\frac{2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac{11}{2}}(c+d x)}+\frac{16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{99 d \cos ^{\frac{9}{2}}(c+d x)} \]
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Rubi [A] time = 1.23302, antiderivative size = 377, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.229, Rules used = {3048, 3047, 3031, 3021, 2748, 2636, 2639, 2641} \[ \frac{2 \left (66 a^2 b^2 (5 A+7 C)+5 a^4 (9 A+11 C)+77 b^4 (A+3 C)\right ) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{231 d}-\frac{8 a b \left (a^2 (7 A+9 C)+3 b^2 (3 A+5 C)\right ) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{15 d}+\frac{2 \left (3 a^2 (9 A+11 C)+16 A b^2\right ) \sin (c+d x) (a+b \cos (c+d x))^2}{231 d \cos ^{\frac{7}{2}}(c+d x)}+\frac{2 \left (9 a^2 b^2 (101 A+143 C)+15 a^4 (9 A+11 C)+64 A b^4\right ) \sin (c+d x)}{693 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{4 a b \left (a^2 (673 A+891 C)+96 A b^2\right ) \sin (c+d x)}{3465 d \cos ^{\frac{5}{2}}(c+d x)}+\frac{8 a b \left (a^2 (7 A+9 C)+3 b^2 (3 A+5 C)\right ) \sin (c+d x)}{15 d \sqrt{\cos (c+d x)}}+\frac{2 A \sin (c+d x) (a+b \cos (c+d x))^4}{11 d \cos ^{\frac{11}{2}}(c+d x)}+\frac{16 A b \sin (c+d x) (a+b \cos (c+d x))^3}{99 d \cos ^{\frac{9}{2}}(c+d x)} \]
Antiderivative was successfully verified.
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Rule 3048
Rule 3047
Rule 3031
Rule 3021
Rule 2748
Rule 2636
Rule 2639
Rule 2641
Rubi steps
\begin{align*} \int \frac{(a+b \cos (c+d x))^4 \left (A+C \cos ^2(c+d x)\right )}{\cos ^{\frac{13}{2}}(c+d x)} \, dx &=\frac{2 A (a+b \cos (c+d x))^4 \sin (c+d x)}{11 d \cos ^{\frac{11}{2}}(c+d x)}+\frac{2}{11} \int \frac{(a+b \cos (c+d x))^3 \left (4 A b+\frac{1}{2} a (9 A+11 C) \cos (c+d x)+\frac{1}{2} b (A+11 C) \cos ^2(c+d x)\right )}{\cos ^{\frac{11}{2}}(c+d x)} \, dx\\ &=\frac{16 A b (a+b \cos (c+d x))^3 \sin (c+d x)}{99 d \cos ^{\frac{9}{2}}(c+d x)}+\frac{2 A (a+b \cos (c+d x))^4 \sin (c+d x)}{11 d \cos ^{\frac{11}{2}}(c+d x)}+\frac{4}{99} \int \frac{(a+b \cos (c+d x))^2 \left (\frac{3}{4} \left (16 A b^2+3 a^2 (9 A+11 C)\right )+\frac{1}{2} a b (73 A+99 C) \cos (c+d x)+\frac{1}{4} b^2 (17 A+99 C) \cos ^2(c+d x)\right )}{\cos ^{\frac{9}{2}}(c+d x)} \, dx\\ &=\frac{2 \left (16 A b^2+3 a^2 (9 A+11 C)\right ) (a+b \cos (c+d x))^2 \sin (c+d x)}{231 d \cos ^{\frac{7}{2}}(c+d x)}+\frac{16 A b (a+b \cos (c+d x))^3 \sin (c+d x)}{99 d \cos ^{\frac{9}{2}}(c+d x)}+\frac{2 A (a+b \cos (c+d x))^4 \sin (c+d x)}{11 d \cos ^{\frac{11}{2}}(c+d x)}+\frac{8}{693} \int \frac{(a+b \cos (c+d x)) \left (\frac{1}{4} b \left (96 A b^2+a^2 (673 A+891 C)\right )+\frac{1}{8} a \left (45 a^2 (9 A+11 C)+b^2 (1381 A+2079 C)\right ) \cos (c+d x)+\frac{1}{8} b \left (9 a^2 (9 A+11 C)+b^2 (167 A+693 C)\right ) \cos ^2(c+d x)\right )}{\cos ^{\frac{7}{2}}(c+d x)} \, dx\\ &=\frac{4 a b \left (96 A b^2+a^2 (673 A+891 C)\right ) \sin (c+d x)}{3465 d \cos ^{\frac{5}{2}}(c+d x)}+\frac{2 \left (16 A b^2+3 a^2 (9 A+11 C)\right ) (a+b \cos (c+d x))^2 \sin (c+d x)}{231 d \cos ^{\frac{7}{2}}(c+d x)}+\frac{16 A b (a+b \cos (c+d x))^3 \sin (c+d x)}{99 d \cos ^{\frac{9}{2}}(c+d x)}+\frac{2 A (a+b \cos (c+d x))^4 \sin (c+d x)}{11 d \cos ^{\frac{11}{2}}(c+d x)}-\frac{16 \int \frac{-\frac{15}{16} \left (64 A b^4+15 a^4 (9 A+11 C)+9 a^2 b^2 (101 A+143 C)\right )-\frac{231}{4} a b \left (3 b^2 (3 A+5 C)+a^2 (7 A+9 C)\right ) \cos (c+d x)-\frac{5}{16} b^2 \left (9 a^2 (9 A+11 C)+b^2 (167 A+693 C)\right ) \cos ^2(c+d x)}{\cos ^{\frac{5}{2}}(c+d x)} \, dx}{3465}\\ &=\frac{4 a b \left (96 A b^2+a^2 (673 A+891 C)\right ) \sin (c+d x)}{3465 d \cos ^{\frac{5}{2}}(c+d x)}+\frac{2 \left (64 A b^4+15 a^4 (9 A+11 C)+9 a^2 b^2 (101 A+143 C)\right ) \sin (c+d x)}{693 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{2 \left (16 A b^2+3 a^2 (9 A+11 C)\right ) (a+b \cos (c+d x))^2 \sin (c+d x)}{231 d \cos ^{\frac{7}{2}}(c+d x)}+\frac{16 A b (a+b \cos (c+d x))^3 \sin (c+d x)}{99 d \cos ^{\frac{9}{2}}(c+d x)}+\frac{2 A (a+b \cos (c+d x))^4 \sin (c+d x)}{11 d \cos ^{\frac{11}{2}}(c+d x)}-\frac{32 \int \frac{-\frac{693}{8} a b \left (3 b^2 (3 A+5 C)+a^2 (7 A+9 C)\right )-\frac{45}{32} \left (77 b^4 (A+3 C)+66 a^2 b^2 (5 A+7 C)+5 a^4 (9 A+11 C)\right ) \cos (c+d x)}{\cos ^{\frac{3}{2}}(c+d x)} \, dx}{10395}\\ &=\frac{4 a b \left (96 A b^2+a^2 (673 A+891 C)\right ) \sin (c+d x)}{3465 d \cos ^{\frac{5}{2}}(c+d x)}+\frac{2 \left (64 A b^4+15 a^4 (9 A+11 C)+9 a^2 b^2 (101 A+143 C)\right ) \sin (c+d x)}{693 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{2 \left (16 A b^2+3 a^2 (9 A+11 C)\right ) (a+b \cos (c+d x))^2 \sin (c+d x)}{231 d \cos ^{\frac{7}{2}}(c+d x)}+\frac{16 A b (a+b \cos (c+d x))^3 \sin (c+d x)}{99 d \cos ^{\frac{9}{2}}(c+d x)}+\frac{2 A (a+b \cos (c+d x))^4 \sin (c+d x)}{11 d \cos ^{\frac{11}{2}}(c+d x)}+\frac{1}{15} \left (4 a b \left (3 b^2 (3 A+5 C)+a^2 (7 A+9 C)\right )\right ) \int \frac{1}{\cos ^{\frac{3}{2}}(c+d x)} \, dx-\frac{1}{231} \left (-77 b^4 (A+3 C)-66 a^2 b^2 (5 A+7 C)-5 a^4 (9 A+11 C)\right ) \int \frac{1}{\sqrt{\cos (c+d x)}} \, dx\\ &=\frac{2 \left (77 b^4 (A+3 C)+66 a^2 b^2 (5 A+7 C)+5 a^4 (9 A+11 C)\right ) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{231 d}+\frac{4 a b \left (96 A b^2+a^2 (673 A+891 C)\right ) \sin (c+d x)}{3465 d \cos ^{\frac{5}{2}}(c+d x)}+\frac{2 \left (64 A b^4+15 a^4 (9 A+11 C)+9 a^2 b^2 (101 A+143 C)\right ) \sin (c+d x)}{693 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{8 a b \left (3 b^2 (3 A+5 C)+a^2 (7 A+9 C)\right ) \sin (c+d x)}{15 d \sqrt{\cos (c+d x)}}+\frac{2 \left (16 A b^2+3 a^2 (9 A+11 C)\right ) (a+b \cos (c+d x))^2 \sin (c+d x)}{231 d \cos ^{\frac{7}{2}}(c+d x)}+\frac{16 A b (a+b \cos (c+d x))^3 \sin (c+d x)}{99 d \cos ^{\frac{9}{2}}(c+d x)}+\frac{2 A (a+b \cos (c+d x))^4 \sin (c+d x)}{11 d \cos ^{\frac{11}{2}}(c+d x)}-\frac{1}{15} \left (4 a b \left (3 b^2 (3 A+5 C)+a^2 (7 A+9 C)\right )\right ) \int \sqrt{\cos (c+d x)} \, dx\\ &=-\frac{8 a b \left (3 b^2 (3 A+5 C)+a^2 (7 A+9 C)\right ) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{15 d}+\frac{2 \left (77 b^4 (A+3 C)+66 a^2 b^2 (5 A+7 C)+5 a^4 (9 A+11 C)\right ) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{231 d}+\frac{4 a b \left (96 A b^2+a^2 (673 A+891 C)\right ) \sin (c+d x)}{3465 d \cos ^{\frac{5}{2}}(c+d x)}+\frac{2 \left (64 A b^4+15 a^4 (9 A+11 C)+9 a^2 b^2 (101 A+143 C)\right ) \sin (c+d x)}{693 d \cos ^{\frac{3}{2}}(c+d x)}+\frac{8 a b \left (3 b^2 (3 A+5 C)+a^2 (7 A+9 C)\right ) \sin (c+d x)}{15 d \sqrt{\cos (c+d x)}}+\frac{2 \left (16 A b^2+3 a^2 (9 A+11 C)\right ) (a+b \cos (c+d x))^2 \sin (c+d x)}{231 d \cos ^{\frac{7}{2}}(c+d x)}+\frac{16 A b (a+b \cos (c+d x))^3 \sin (c+d x)}{99 d \cos ^{\frac{9}{2}}(c+d x)}+\frac{2 A (a+b \cos (c+d x))^4 \sin (c+d x)}{11 d \cos ^{\frac{11}{2}}(c+d x)}\\ \end{align*}
Mathematica [A] time = 4.45073, size = 284, normalized size = 0.75 \[ \frac{10 \left (66 a^2 b^2 (5 A+7 C)+5 a^4 (9 A+11 C)+77 b^4 (A+3 C)\right ) F\left (\left .\frac{1}{2} (c+d x)\right |2\right )-616 \left (a^3 b (7 A+9 C)+3 a b^3 (3 A+5 C)\right ) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )+\frac{45 \left (\left (66 a^2 A b^2+a^4 (9 A+11 C)\right ) \sin (2 (c+d x))+14 a^4 A \tan (c+d x)\right )+2 \sin (c+d x) \left (924 a b \left (a^2 (7 A+9 C)+3 b^2 (3 A+5 C)\right ) \cos ^4(c+d x)+15 \left (66 a^2 b^2 (5 A+7 C)+5 a^4 (9 A+11 C)+77 A b^4\right ) \cos ^3(c+d x)+308 a b \left (a^2 (7 A+9 C)+9 A b^2\right ) \cos ^2(c+d x)+1540 a^3 A b\right )}{3 \cos ^{\frac{9}{2}}(c+d x)}}{1155 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 2.655, size = 1521, normalized size = 4. \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (C \cos \left (d x + c\right )^{2} + A\right )}{\left (b \cos \left (d x + c\right ) + a\right )}^{4}}{\cos \left (d x + c\right )^{\frac{13}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{C b^{4} \cos \left (d x + c\right )^{6} + 4 \, C a b^{3} \cos \left (d x + c\right )^{5} + 4 \, A a^{3} b \cos \left (d x + c\right ) + A a^{4} +{\left (6 \, C a^{2} b^{2} + A b^{4}\right )} \cos \left (d x + c\right )^{4} + 4 \,{\left (C a^{3} b + A a b^{3}\right )} \cos \left (d x + c\right )^{3} +{\left (C a^{4} + 6 \, A a^{2} b^{2}\right )} \cos \left (d x + c\right )^{2}}{\cos \left (d x + c\right )^{\frac{13}{2}}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (C \cos \left (d x + c\right )^{2} + A\right )}{\left (b \cos \left (d x + c\right ) + a\right )}^{4}}{\cos \left (d x + c\right )^{\frac{13}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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